4(2z+1)-8=36

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Solution for 4(2z+1)-8=36 equation: 



4(2z+1)-8=36

We move all terms to the left:

4(2z+1)-8-(36)=0

We add all the numbers together, and all the variables

4(2z+1)-44=0

We multiply parentheses

8z+4-44=0

We add all the numbers together, and all the variables

8z-40=0

We move all terms containing z to the left, all other terms to the right

8z=40

z=40/8

z=5

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