4(2z+1)=15

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Solution for 4(2z+1)=15 equation: 



4(2z+1)=15

We move all terms to the left:

4(2z+1)-(15)=0

We multiply parentheses

8z+4-15=0

We add all the numbers together, and all the variables

8z-11=0

We move all terms containing z to the left, all other terms to the right

8z=11

z=11/8

z=1+3/8

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