4(2z+1)=64

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Solution for 4(2z+1)=64 equation: 



4(2z+1)=64

We move all terms to the left:

4(2z+1)-(64)=0

We multiply parentheses

8z+4-64=0

We add all the numbers together, and all the variables

8z-60=0

We move all terms containing z to the left, all other terms to the right

8z=60

z=60/8

z=7+1/2

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