4(2z+3)=-28

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Solution for 4(2z+3)=-28 equation:



4(2z+3)=-28
We move all terms to the left:
4(2z+3)-(-28)=0
We add all the numbers together, and all the variables
4(2z+3)+28=0
We multiply parentheses
8z+12+28=0
We add all the numbers together, and all the variables
8z+40=0
We move all terms containing z to the left, all other terms to the right
8z=-40
z=-40/8
z=-5

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