4(2z+3)=8(z-3)+36

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Solution for 4(2z+3)=8(z-3)+36 equation: 


Simplifying
4(2z + 3) = 8(z + -3) + 36

Reorder the terms:
4(3 + 2z) = 8(z + -3) + 36
(3 * 4 + 2z * 4) = 8(z + -3) + 36
(12 + 8z) = 8(z + -3) + 36

Reorder the terms:
12 + 8z = 8(-3 + z) + 36
12 + 8z = (-3 * 8 + z * 8) + 36
12 + 8z = (-24 + 8z) + 36

Reorder the terms:
12 + 8z = -24 + 36 + 8z

Combine like terms: -24 + 36 = 12
12 + 8z = 12 + 8z

Add '-12' to each side of the equation.
12 + -12 + 8z = 12 + -12 + 8z

Combine like terms: 12 + -12 = 0
0 + 8z = 12 + -12 + 8z
8z = 12 + -12 + 8z

Combine like terms: 12 + -12 = 0
8z = 0 + 8z
8z = 8z

Add '-8z' to each side of the equation.
8z + -8z = 8z + -8z

Combine like terms: 8z + -8z = 0
0 = 8z + -8z

Combine like terms: 8z + -8z = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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