4(2z+4)=4z+32

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Solution for 4(2z+4)=4z+32 equation:


Simplifying
4(2z + 4) = 4z + 32

Reorder the terms:
4(4 + 2z) = 4z + 32
(4 * 4 + 2z * 4) = 4z + 32
(16 + 8z) = 4z + 32

Reorder the terms:
16 + 8z = 32 + 4z

Solving
16 + 8z = 32 + 4z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-4z' to each side of the equation.
16 + 8z + -4z = 32 + 4z + -4z

Combine like terms: 8z + -4z = 4z
16 + 4z = 32 + 4z + -4z

Combine like terms: 4z + -4z = 0
16 + 4z = 32 + 0
16 + 4z = 32

Add '-16' to each side of the equation.
16 + -16 + 4z = 32 + -16

Combine like terms: 16 + -16 = 0
0 + 4z = 32 + -16
4z = 32 + -16

Combine like terms: 32 + -16 = 16
4z = 16

Divide each side by '4'.
z = 4

Simplifying
z = 4

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