4(2z+7)=7(z+4)+z

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Solution for 4(2z+7)=7(z+4)+z equation: 


Simplifying
4(2z + 7) = 7(z + 4) + z

Reorder the terms:
4(7 + 2z) = 7(z + 4) + z
(7 * 4 + 2z * 4) = 7(z + 4) + z
(28 + 8z) = 7(z + 4) + z

Reorder the terms:
28 + 8z = 7(4 + z) + z
28 + 8z = (4 * 7 + z * 7) + z
28 + 8z = (28 + 7z) + z

Combine like terms: 7z + z = 8z
28 + 8z = 28 + 8z

Add '-28' to each side of the equation.
28 + -28 + 8z = 28 + -28 + 8z

Combine like terms: 28 + -28 = 0
0 + 8z = 28 + -28 + 8z
8z = 28 + -28 + 8z

Combine like terms: 28 + -28 = 0
8z = 0 + 8z
8z = 8z

Add '-8z' to each side of the equation.
8z + -8z = 8z + -8z

Combine like terms: 8z + -8z = 0
0 = 8z + -8z

Combine like terms: 8z + -8z = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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