4(2z-1)-3(z+2)=3(z+1)

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Solution for 4(2z-1)-3(z+2)=3(z+1) equation: 



4(2z-1)-3(z+2)=3(z+1)

We move all terms to the left:

4(2z-1)-3(z+2)-(3(z+1))=0

We multiply parentheses

8z-3z-(3(z+1))-4-6=0



We calculate terms in parentheses: -(3(z+1)), so:

3(z+1)

We multiply parentheses

3z+3

Back to the equation:

-(3z+3)



We add all the numbers together, and all the variables

5z-(3z+3)-10=0

We get rid of parentheses

5z-3z-3-10=0

We add all the numbers together, and all the variables

2z-13=0

We move all terms containing z to the left, all other terms to the right

2z=13

z=13/2

z=6+1/2

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