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4(2z-1)-3(z+2)=3(z+1)
We move all terms to the left:
4(2z-1)-3(z+2)-(3(z+1))=0
We multiply parentheses
8z-3z-(3(z+1))-4-6=0
We calculate terms in parentheses: -(3(z+1)), so:We add all the numbers together, and all the variables
3(z+1)
We multiply parentheses
3z+3
Back to the equation:
-(3z+3)
5z-(3z+3)-10=0
We get rid of parentheses
5z-3z-3-10=0
We add all the numbers together, and all the variables
2z-13=0
We move all terms containing z to the left, all other terms to the right
2z=13
z=13/2
z=6+1/2
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