4(2z-1)-3(z+4)=3(z+1)

Solution for 4(2z-1)-3(z+4)=3(z+1) equation:

Simplifying
4(2z + -1) + -3(z + 4) = 3(z + 1)

Reorder the terms:
4(-1 + 2z) + -3(z + 4) = 3(z + 1)
(-1 * 4 + 2z * 4) + -3(z + 4) = 3(z + 1)
(-4 + 8z) + -3(z + 4) = 3(z + 1)

Reorder the terms:
-4 + 8z + -3(4 + z) = 3(z + 1)
-4 + 8z + (4 * -3 + z * -3) = 3(z + 1)
-4 + 8z + (-12 + -3z) = 3(z + 1)

Reorder the terms:
-4 + -12 + 8z + -3z = 3(z + 1)

Combine like terms: -4 + -12 = -16
-16 + 8z + -3z = 3(z + 1)

Combine like terms: 8z + -3z = 5z
-16 + 5z = 3(z + 1)

Reorder the terms:
-16 + 5z = 3(1 + z)
-16 + 5z = (1 * 3 + z * 3)
-16 + 5z = (3 + 3z)

Solving
-16 + 5z = 3 + 3z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-3z' to each side of the equation.
-16 + 5z + -3z = 3 + 3z + -3z

Combine like terms: 5z + -3z = 2z
-16 + 2z = 3 + 3z + -3z

Combine like terms: 3z + -3z = 0
-16 + 2z = 3 + 0
-16 + 2z = 3

Add '16' to each side of the equation.
-16 + 16 + 2z = 3 + 16

Combine like terms: -16 + 16 = 0
0 + 2z = 3 + 16
2z = 3 + 16

Combine like terms: 3 + 16 = 19
2z = 19

Divide each side by '2'.
z = 9.5

Simplifying
z = 9.5