4(2z-1)-3(z+4)=4(z+1)

Solution for 4(2z-1)-3(z+4)=4(z+1) equation:

Simplifying
4(2z + -1) + -3(z + 4) = 4(z + 1)

Reorder the terms:
4(-1 + 2z) + -3(z + 4) = 4(z + 1)
(-1 * 4 + 2z * 4) + -3(z + 4) = 4(z + 1)
(-4 + 8z) + -3(z + 4) = 4(z + 1)

Reorder the terms:
-4 + 8z + -3(4 + z) = 4(z + 1)
-4 + 8z + (4 * -3 + z * -3) = 4(z + 1)
-4 + 8z + (-12 + -3z) = 4(z + 1)

Reorder the terms:
-4 + -12 + 8z + -3z = 4(z + 1)

Combine like terms: -4 + -12 = -16
-16 + 8z + -3z = 4(z + 1)

Combine like terms: 8z + -3z = 5z
-16 + 5z = 4(z + 1)

Reorder the terms:
-16 + 5z = 4(1 + z)
-16 + 5z = (1 * 4 + z * 4)
-16 + 5z = (4 + 4z)

Solving
-16 + 5z = 4 + 4z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-4z' to each side of the equation.
-16 + 5z + -4z = 4 + 4z + -4z

Combine like terms: 5z + -4z = 1z
-16 + 1z = 4 + 4z + -4z

Combine like terms: 4z + -4z = 0
-16 + 1z = 4 + 0
-16 + 1z = 4

Add '16' to each side of the equation.
-16 + 16 + 1z = 4 + 16

Combine like terms: -16 + 16 = 0
0 + 1z = 4 + 16
1z = 4 + 16

Combine like terms: 4 + 16 = 20
1z = 20

Divide each side by '1'.
z = 20

Simplifying
z = 20