4(2z-1)=2-3(4z-5)

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Solution for 4(2z-1)=2-3(4z-5) equation: 



4(2z-1)=2-3(4z-5)

We move all terms to the left:

4(2z-1)-(2-3(4z-5))=0

We multiply parentheses

8z-(2-3(4z-5))-4=0



We calculate terms in parentheses: -(2-3(4z-5)), so:

2-3(4z-5)

determiningTheFunctionDomain
-3(4z-5)+2

We multiply parentheses

-12z+15+2

We add all the numbers together, and all the variables

-12z+17

Back to the equation:

-(-12z+17)



We get rid of parentheses

8z+12z-17-4=0

We add all the numbers together, and all the variables

20z-21=0

We move all terms containing z to the left, all other terms to the right

20z=21

z=21/20

z=1+1/20

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