4(2z-1)=8z-4

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Solution for 4(2z-1)=8z-4 equation:


Simplifying
4(2z + -1) = 8z + -4

Reorder the terms:
4(-1 + 2z) = 8z + -4
(-1 * 4 + 2z * 4) = 8z + -4
(-4 + 8z) = 8z + -4

Reorder the terms:
-4 + 8z = -4 + 8z

Add '4' to each side of the equation.
-4 + 4 + 8z = -4 + 4 + 8z

Combine like terms: -4 + 4 = 0
0 + 8z = -4 + 4 + 8z
8z = -4 + 4 + 8z

Combine like terms: -4 + 4 = 0
8z = 0 + 8z
8z = 8z

Add '-8z' to each side of the equation.
8z + -8z = 8z + -8z

Combine like terms: 8z + -8z = 0
0 = 8z + -8z

Combine like terms: 8z + -8z = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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