4(2z-2)=4(3z-2)

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Solution for 4(2z-2)=4(3z-2) equation: 



4(2z-2)=4(3z-2)

We move all terms to the left:

4(2z-2)-(4(3z-2))=0

We multiply parentheses

8z-(4(3z-2))-8=0



We calculate terms in parentheses: -(4(3z-2)), so:

4(3z-2)

We multiply parentheses

12z-8

Back to the equation:

-(12z-8)



We get rid of parentheses

8z-12z+8-8=0

We add all the numbers together, and all the variables

-4z=0

z=0/-4

z=0

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