4(2z-2)=7(z-2)

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Solution for 4(2z-2)=7(z-2) equation:


Simplifying
4(2z + -2) = 7(z + -2)

Reorder the terms:
4(-2 + 2z) = 7(z + -2)
(-2 * 4 + 2z * 4) = 7(z + -2)
(-8 + 8z) = 7(z + -2)

Reorder the terms:
-8 + 8z = 7(-2 + z)
-8 + 8z = (-2 * 7 + z * 7)
-8 + 8z = (-14 + 7z)

Solving
-8 + 8z = -14 + 7z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-7z' to each side of the equation.
-8 + 8z + -7z = -14 + 7z + -7z

Combine like terms: 8z + -7z = 1z
-8 + 1z = -14 + 7z + -7z

Combine like terms: 7z + -7z = 0
-8 + 1z = -14 + 0
-8 + 1z = -14

Add '8' to each side of the equation.
-8 + 8 + 1z = -14 + 8

Combine like terms: -8 + 8 = 0
0 + 1z = -14 + 8
1z = -14 + 8

Combine like terms: -14 + 8 = -6
1z = -6

Divide each side by '1'.
z = -6

Simplifying
z = -6

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