4(2z-3)+3=2(2+3)-3(z+1)

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Solution for 4(2z-3)+3=2(2+3)-3(z+1) equation: 



4(2z-3)+3=2(2+3)-3(z+1)

We move all terms to the left:

4(2z-3)+3-(2(2+3)-3(z+1))=0

We add all the numbers together, and all the variables

4(2z-3)-(25-3(z+1))+3=0

We multiply parentheses

8z-(25-3(z+1))-12+3=0



We calculate terms in parentheses: -(25-3(z+1)), so:

25-3(z+1)

determiningTheFunctionDomain
-3(z+1)+25

We multiply parentheses

-3z-3+25

We add all the numbers together, and all the variables

-3z+22

Back to the equation:

-(-3z+22)



We add all the numbers together, and all the variables

8z-(-3z+22)-9=0

We get rid of parentheses

8z+3z-22-9=0

We add all the numbers together, and all the variables

11z-31=0

We move all terms containing z to the left, all other terms to the right

11z=31

z=31/11

z=2+9/11

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