4(2z-3)+3=2(2+3)-3(z+1)

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Solution for 4(2z-3)+3=2(2+3)-3(z+1) equation:



4(2z-3)+3=2(2+3)-3(z+1)
We move all terms to the left:
4(2z-3)+3-(2(2+3)-3(z+1))=0
We add all the numbers together, and all the variables
4(2z-3)-(25-3(z+1))+3=0
We multiply parentheses
8z-(25-3(z+1))-12+3=0
We calculate terms in parentheses: -(25-3(z+1)), so:
25-3(z+1)
determiningTheFunctionDomain -3(z+1)+25
We multiply parentheses
-3z-3+25
We add all the numbers together, and all the variables
-3z+22
Back to the equation:
-(-3z+22)
We add all the numbers together, and all the variables
8z-(-3z+22)-9=0
We get rid of parentheses
8z+3z-22-9=0
We add all the numbers together, and all the variables
11z-31=0
We move all terms containing z to the left, all other terms to the right
11z=31
z=31/11
z=2+9/11

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