4(2z-3)/7=3z-11

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Solution for 4(2z-3)/7=3z-11 equation: 


z in (-oo:+oo)

(4*(2*z-3))/7 = 3*z-11 // - 3*z-11

(4*(2*z-3))/7-(3*z)+11 = 0

(4*(2*z-3))/7-3*z+11 = 0

(4*(2*z-3))/7+(-3*7*z)/7+(7*11)/7 = 0

4*(2*z-3)-3*7*z+7*11 = 0

77-13*z-12 = 0

65-13*z = 0

(65-13*z)/7 = 0

(65-13*z)/7 = 0 // * 7

65-13*z = 0

65-13*z = 0 // - 65

-13*z = -65 // : -13

z = -65/(-13)

z = 5

z = 5

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