4(2z-3)=7(z-4)

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Solution for 4(2z-3)=7(z-4) equation:


Simplifying
4(2z + -3) = 7(z + -4)

Reorder the terms:
4(-3 + 2z) = 7(z + -4)
(-3 * 4 + 2z * 4) = 7(z + -4)
(-12 + 8z) = 7(z + -4)

Reorder the terms:
-12 + 8z = 7(-4 + z)
-12 + 8z = (-4 * 7 + z * 7)
-12 + 8z = (-28 + 7z)

Solving
-12 + 8z = -28 + 7z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-7z' to each side of the equation.
-12 + 8z + -7z = -28 + 7z + -7z

Combine like terms: 8z + -7z = 1z
-12 + 1z = -28 + 7z + -7z

Combine like terms: 7z + -7z = 0
-12 + 1z = -28 + 0
-12 + 1z = -28

Add '12' to each side of the equation.
-12 + 12 + 1z = -28 + 12

Combine like terms: -12 + 12 = 0
0 + 1z = -28 + 12
1z = -28 + 12

Combine like terms: -28 + 12 = -16
1z = -16

Divide each side by '1'.
z = -16

Simplifying
z = -16

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