4(2z-4)=-7(z+4)

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Solution for 4(2z-4)=-7(z+4) equation: 



4(2z-4)=-7(z+4)

We move all terms to the left:

4(2z-4)-(-7(z+4))=0

We multiply parentheses

8z-(-7(z+4))-16=0



We calculate terms in parentheses: -(-7(z+4)), so:

-7(z+4)

We multiply parentheses

-7z-28

Back to the equation:

-(-7z-28)



We get rid of parentheses

8z+7z+28-16=0

We add all the numbers together, and all the variables

15z+12=0

We move all terms containing z to the left, all other terms to the right

15z=-12

z=-12/15

z=-4/5

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