4(2z-4)=7(z+5)

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Solution for 4(2z-4)=7(z+5) equation:


Simplifying
4(2z + -4) = 7(z + 5)

Reorder the terms:
4(-4 + 2z) = 7(z + 5)
(-4 * 4 + 2z * 4) = 7(z + 5)
(-16 + 8z) = 7(z + 5)

Reorder the terms:
-16 + 8z = 7(5 + z)
-16 + 8z = (5 * 7 + z * 7)
-16 + 8z = (35 + 7z)

Solving
-16 + 8z = 35 + 7z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-7z' to each side of the equation.
-16 + 8z + -7z = 35 + 7z + -7z

Combine like terms: 8z + -7z = 1z
-16 + 1z = 35 + 7z + -7z

Combine like terms: 7z + -7z = 0
-16 + 1z = 35 + 0
-16 + 1z = 35

Add '16' to each side of the equation.
-16 + 16 + 1z = 35 + 16

Combine like terms: -16 + 16 = 0
0 + 1z = 35 + 16
1z = 35 + 16

Combine like terms: 35 + 16 = 51
1z = 51

Divide each side by '1'.
z = 51

Simplifying
z = 51

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