4(2z-4)=7(z-3)

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Solution for 4(2z-4)=7(z-3) equation:


Simplifying
4(2z + -4) = 7(z + -3)

Reorder the terms:
4(-4 + 2z) = 7(z + -3)
(-4 * 4 + 2z * 4) = 7(z + -3)
(-16 + 8z) = 7(z + -3)

Reorder the terms:
-16 + 8z = 7(-3 + z)
-16 + 8z = (-3 * 7 + z * 7)
-16 + 8z = (-21 + 7z)

Solving
-16 + 8z = -21 + 7z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-7z' to each side of the equation.
-16 + 8z + -7z = -21 + 7z + -7z

Combine like terms: 8z + -7z = 1z
-16 + 1z = -21 + 7z + -7z

Combine like terms: 7z + -7z = 0
-16 + 1z = -21 + 0
-16 + 1z = -21

Add '16' to each side of the equation.
-16 + 16 + 1z = -21 + 16

Combine like terms: -16 + 16 = 0
0 + 1z = -21 + 16
1z = -21 + 16

Combine like terms: -21 + 16 = -5
1z = -5

Divide each side by '1'.
z = -5

Simplifying
z = -5

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