4(2z-5)=-18-2(1-4z)

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Solution for 4(2z-5)=-18-2(1-4z) equation: 



4(2z-5)=-18-2(1-4z)

We move all terms to the left:

4(2z-5)-(-18-2(1-4z))=0

We add all the numbers together, and all the variables

4(2z-5)-(-18-2(-4z+1))=0

We multiply parentheses

8z-(-18-2(-4z+1))-20=0



We calculate terms in parentheses: -(-18-2(-4z+1)), so:

-18-2(-4z+1)

determiningTheFunctionDomain
-2(-4z+1)-18

We multiply parentheses

8z-2-18

We add all the numbers together, and all the variables

8z-20

Back to the equation:

-(8z-20)



We get rid of parentheses

8z-8z+20-20=0

We add all the numbers together, and all the variables

=0

z=0/1

z=0

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