4(2z-5)=7(z+5)

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Solution for 4(2z-5)=7(z+5) equation:


Simplifying
4(2z + -5) = 7(z + 5)

Reorder the terms:
4(-5 + 2z) = 7(z + 5)
(-5 * 4 + 2z * 4) = 7(z + 5)
(-20 + 8z) = 7(z + 5)

Reorder the terms:
-20 + 8z = 7(5 + z)
-20 + 8z = (5 * 7 + z * 7)
-20 + 8z = (35 + 7z)

Solving
-20 + 8z = 35 + 7z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-7z' to each side of the equation.
-20 + 8z + -7z = 35 + 7z + -7z

Combine like terms: 8z + -7z = 1z
-20 + 1z = 35 + 7z + -7z

Combine like terms: 7z + -7z = 0
-20 + 1z = 35 + 0
-20 + 1z = 35

Add '20' to each side of the equation.
-20 + 20 + 1z = 35 + 20

Combine like terms: -20 + 20 = 0
0 + 1z = 35 + 20
1z = 35 + 20

Combine like terms: 35 + 20 = 55
1z = 55

Divide each side by '1'.
z = 55

Simplifying
z = 55

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