4(2z-8)=7(z-2)

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Solution for 4(2z-8)=7(z-2) equation:



4(2z-8)=7(z-2)
We move all terms to the left:
4(2z-8)-(7(z-2))=0
We multiply parentheses
8z-(7(z-2))-32=0
We calculate terms in parentheses: -(7(z-2)), so:
7(z-2)
We multiply parentheses
7z-14
Back to the equation:
-(7z-14)
We get rid of parentheses
8z-7z+14-32=0
We add all the numbers together, and all the variables
z-18=0
We move all terms containing z to the left, all other terms to the right
z=18

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