4(3(2)-y)=10

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Solution for 4(3(2)-y)=10 equation: 



4(3(2)-y)=10

We move all terms to the left:

4(3(2)-y)-(10)=0

We add all the numbers together, and all the variables

4(-1y+32)-10=0

We multiply parentheses

-4y+128-10=0

We add all the numbers together, and all the variables

-4y+118=0

We move all terms containing y to the left, all other terms to the right

-4y=-118

y=-118/-4

y=29+1/2

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