4(3+2b)+3=72

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Solution for 4(3+2b)+3=72 equation: 



4(3+2b)+3=72

We move all terms to the left:

4(3+2b)+3-(72)=0

We add all the numbers together, and all the variables

4(2b+3)+3-72=0

We add all the numbers together, and all the variables

4(2b+3)-69=0

We multiply parentheses

8b+12-69=0

We add all the numbers together, and all the variables

8b-57=0

We move all terms containing b to the left, all other terms to the right

8b=57

b=57/8

b=7+1/8

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