4(3+2x)+5(4-3x)=68

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Solution for 4(3+2x)+5(4-3x)=68 equation: 



4(3+2x)+5(4-3x)=68

We move all terms to the left:

4(3+2x)+5(4-3x)-(68)=0

We add all the numbers together, and all the variables

4(2x+3)+5(-3x+4)-68=0

We multiply parentheses

8x-15x+12+20-68=0

We add all the numbers together, and all the variables

-7x-36=0

We move all terms containing x to the left, all other terms to the right

-7x=36

x=36/-7

x=-5+1/7

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