4(3+4)-u=6+3(u+2)

Solution for 4(3+4)-u=6+3(u+2) equation:

4(3+4)-u=6+3(u+2)

We move all terms to the left:

4(3+4)-u-(6+3(u+2))=0

We add all the numbers together, and all the variables

-u-(6+3(u+2))+47=0

We add all the numbers together, and all the variables

-1u-(6+3(u+2))+47=0


We calculate terms in parentheses: -(6+3(u+2)), so:

6+3(u+2)

determiningTheFunctionDomain
3(u+2)+6

We multiply parentheses

3u+6+6

We add all the numbers together, and all the variables

3u+12

Back to the equation:

-(3u+12)


We get rid of parentheses

-1u-3u-12+47=0

We add all the numbers together, and all the variables

-4u+35=0

We move all terms containing u to the left, all other terms to the right

-4u=-35

u=-35/-4

u=8+3/4