4(3+4r)=2(6+8r)

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Solution for 4(3+4r)=2(6+8r) equation: 



4(3+4r)=2(6+8r)

We move all terms to the left:

4(3+4r)-(2(6+8r))=0

We add all the numbers together, and all the variables

4(4r+3)-(2(8r+6))=0

We multiply parentheses

16r-(2(8r+6))+12=0



We calculate terms in parentheses: -(2(8r+6)), so:

2(8r+6)

We multiply parentheses

16r+12

Back to the equation:

-(16r+12)



We get rid of parentheses

16r-16r-12+12=0

We add all the numbers together, and all the variables

=0

r=0/1

r=0

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