4(3+7x)=7x+33

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Solution for 4(3+7x)=7x+33 equation: 



4(3+7x)=7x+33

We move all terms to the left:

4(3+7x)-(7x+33)=0

We add all the numbers together, and all the variables

4(7x+3)-(7x+33)=0

We multiply parentheses

28x-(7x+33)+12=0

We get rid of parentheses

28x-7x-33+12=0

We add all the numbers together, and all the variables

21x-21=0

We move all terms containing x to the left, all other terms to the right

21x=21

x=21/21

x=1

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