4(3+a)+6=17+5a

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Solution for 4(3+a)+6=17+5a equation: 



4(3+a)+6=17+5a

We move all terms to the left:

4(3+a)+6-(17+5a)=0

We add all the numbers together, and all the variables

4(a+3)-(5a+17)+6=0

We multiply parentheses

4a-(5a+17)+12+6=0

We get rid of parentheses

4a-5a-17+12+6=0

We add all the numbers together, and all the variables

-1a+1=0

We move all terms containing a to the left, all other terms to the right

-a=-1

a=-1/-1

a=1

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