4(3+c)+c+c=4

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Solution for 4(3+c)+c+c=4 equation: 



4(3+c)+c+c=4

We move all terms to the left:

4(3+c)+c+c-(4)=0

We add all the numbers together, and all the variables

4(c+3)+c+c-4=0

We add all the numbers together, and all the variables

2c+4(c+3)-4=0

We multiply parentheses

2c+4c+12-4=0

We add all the numbers together, and all the variables

6c+8=0

We move all terms containing c to the left, all other terms to the right

6c=-8

c=-8/6

c=-1+1/3

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