4(3+c)+c=c+14

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Solution for 4(3+c)+c=c+14 equation: 



4(3+c)+c=c+14

We move all terms to the left:

4(3+c)+c-(c+14)=0

We add all the numbers together, and all the variables

4(c+3)+c-(c+14)=0

We add all the numbers together, and all the variables

c+4(c+3)-(c+14)=0

We multiply parentheses

c+4c-(c+14)+12=0

We get rid of parentheses

c+4c-c-14+12=0

We add all the numbers together, and all the variables

4c-2=0

We move all terms containing c to the left, all other terms to the right

4c=2

c=2/4

c=1/2

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