4(3+c)+c=c+4=

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Solution for 4(3+c)+c=c+4= equation: 



4(3+c)+c=c+4=

We move all terms to the left:

4(3+c)+c-(c+4)=0

We add all the numbers together, and all the variables

4(c+3)+c-(c+4)=0

We add all the numbers together, and all the variables

c+4(c+3)-(c+4)=0

We multiply parentheses

c+4c-(c+4)+12=0

We get rid of parentheses

c+4c-c-4+12=0

We add all the numbers together, and all the variables

4c+8=0

We move all terms containing c to the left, all other terms to the right

4c=-8

c=-8/4

c=-2

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