4(3+c)=3(c-1)

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Solution for 4(3+c)=3(c-1) equation: 


Simplifying
4(3 + c) = 3(c + -1)
(3 * 4 + c * 4) = 3(c + -1)
(12 + 4c) = 3(c + -1)

Reorder the terms:
12 + 4c = 3(-1 + c)
12 + 4c = (-1 * 3 + c * 3)
12 + 4c = (-3 + 3c)

Solving
12 + 4c = -3 + 3c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-3c' to each side of the equation.
12 + 4c + -3c = -3 + 3c + -3c

Combine like terms: 4c + -3c = 1c
12 + 1c = -3 + 3c + -3c

Combine like terms: 3c + -3c = 0
12 + 1c = -3 + 0
12 + 1c = -3

Add '-12' to each side of the equation.
12 + -12 + 1c = -3 + -12

Combine like terms: 12 + -12 = 0
0 + 1c = -3 + -12
1c = -3 + -12

Combine like terms: -3 + -12 = -15
1c = -15

Divide each side by '1'.
c = -15

Simplifying
c = -15

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