4(3+c)=3(c-5)

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Solution for 4(3+c)=3(c-5) equation: 


Simplifying
4(3 + c) = 3(c + -5)
(3 * 4 + c * 4) = 3(c + -5)
(12 + 4c) = 3(c + -5)

Reorder the terms:
12 + 4c = 3(-5 + c)
12 + 4c = (-5 * 3 + c * 3)
12 + 4c = (-15 + 3c)

Solving
12 + 4c = -15 + 3c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-3c' to each side of the equation.
12 + 4c + -3c = -15 + 3c + -3c

Combine like terms: 4c + -3c = 1c
12 + 1c = -15 + 3c + -3c

Combine like terms: 3c + -3c = 0
12 + 1c = -15 + 0
12 + 1c = -15

Add '-12' to each side of the equation.
12 + -12 + 1c = -15 + -12

Combine like terms: 12 + -12 = 0
0 + 1c = -15 + -12
1c = -15 + -12

Combine like terms: -15 + -12 = -27
1c = -27

Divide each side by '1'.
c = -27

Simplifying
c = -27

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