4(3+n)=9n-18

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Solution for 4(3+n)=9n-18 equation: 



4(3+n)=9n-18

We move all terms to the left:

4(3+n)-(9n-18)=0

We add all the numbers together, and all the variables

4(n+3)-(9n-18)=0

We multiply parentheses

4n-(9n-18)+12=0

We get rid of parentheses

4n-9n+18+12=0

We add all the numbers together, and all the variables

-5n+30=0

We move all terms containing n to the left, all other terms to the right

-5n=-30

n=-30/-5

n=+6

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