4(3+r)+10=-11(r-6)+1

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Solution for 4(3+r)+10=-11(r-6)+1 equation: 



4(3+r)+10=-11(r-6)+1

We move all terms to the left:

4(3+r)+10-(-11(r-6)+1)=0

We add all the numbers together, and all the variables

4(r+3)-(-11(r-6)+1)+10=0

We multiply parentheses

4r-(-11(r-6)+1)+12+10=0



We calculate terms in parentheses: -(-11(r-6)+1), so:

-11(r-6)+1

We multiply parentheses

-11r+66+1

We add all the numbers together, and all the variables

-11r+67

Back to the equation:

-(-11r+67)



We add all the numbers together, and all the variables

4r-(-11r+67)+22=0

We get rid of parentheses

4r+11r-67+22=0

We add all the numbers together, and all the variables

15r-45=0

We move all terms containing r to the left, all other terms to the right

15r=45

r=45/15

r=3

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