4(3+u)-u=6+3(u+2)

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Solution for 4(3+u)-u=6+3(u+2) equation: 


Simplifying
4(3 + u) + -1u = 6 + 3(u + 2)
(3 * 4 + u * 4) + -1u = 6 + 3(u + 2)
(12 + 4u) + -1u = 6 + 3(u + 2)

Combine like terms: 4u + -1u = 3u
12 + 3u = 6 + 3(u + 2)

Reorder the terms:
12 + 3u = 6 + 3(2 + u)
12 + 3u = 6 + (2 * 3 + u * 3)
12 + 3u = 6 + (6 + 3u)

Combine like terms: 6 + 6 = 12
12 + 3u = 12 + 3u

Add '-12' to each side of the equation.
12 + -12 + 3u = 12 + -12 + 3u

Combine like terms: 12 + -12 = 0
0 + 3u = 12 + -12 + 3u
3u = 12 + -12 + 3u

Combine like terms: 12 + -12 = 0
3u = 0 + 3u
3u = 3u

Add '-3u' to each side of the equation.
3u + -3u = 3u + -3u

Combine like terms: 3u + -3u = 0
0 = 3u + -3u

Combine like terms: 3u + -3u = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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