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4(3+v)-3=6+3(v+2)
We move all terms to the left:
4(3+v)-3-(6+3(v+2))=0
We add all the numbers together, and all the variables
4(v+3)-(6+3(v+2))-3=0
We multiply parentheses
4v-(6+3(v+2))+12-3=0
We calculate terms in parentheses: -(6+3(v+2)), so:We add all the numbers together, and all the variables
6+3(v+2)
determiningTheFunctionDomain 3(v+2)+6
We multiply parentheses
3v+6+6
We add all the numbers together, and all the variables
3v+12
Back to the equation:
-(3v+12)
4v-(3v+12)+9=0
We get rid of parentheses
4v-3v-12+9=0
We add all the numbers together, and all the variables
v-3=0
We move all terms containing v to the left, all other terms to the right
v=3
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