4(3+v)-6=6+3(v+2)

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Solution for 4(3+v)-6=6+3(v+2) equation: 



4(3+v)-6=6+3(v+2)

We move all terms to the left:

4(3+v)-6-(6+3(v+2))=0

We add all the numbers together, and all the variables

4(v+3)-(6+3(v+2))-6=0

We multiply parentheses

4v-(6+3(v+2))+12-6=0



We calculate terms in parentheses: -(6+3(v+2)), so:

6+3(v+2)

determiningTheFunctionDomain
3(v+2)+6

We multiply parentheses

3v+6+6

We add all the numbers together, and all the variables

3v+12

Back to the equation:

-(3v+12)



We add all the numbers together, and all the variables

4v-(3v+12)+6=0

We get rid of parentheses

4v-3v-12+6=0

We add all the numbers together, and all the variables

v-6=0

We move all terms containing v to the left, all other terms to the right

v=6

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