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4(3+x)-x=6+3(x+2
We move all terms to the left:
4(3+x)-x-(6+3(x+2)=0
We add all the numbers together, and all the variables
4(x+3)-x-(6+3(x+2)=0
We add all the numbers together, and all the variables
-1x+4(x+3)-(6+3(x+2)=0
We multiply parentheses
-1x+4x-(6+3(x+2)+12=0
We add all the numbers together, and all the variables
3x-(6+3(x+2)+12=0
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