4(3+x)=3(4x-1)-49

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Solution for 4(3+x)=3(4x-1)-49 equation: 



4(3+x)=3(4x-1)-49

We move all terms to the left:

4(3+x)-(3(4x-1)-49)=0

We add all the numbers together, and all the variables

4(x+3)-(3(4x-1)-49)=0

We multiply parentheses

4x-(3(4x-1)-49)+12=0



We calculate terms in parentheses: -(3(4x-1)-49), so:

3(4x-1)-49

We multiply parentheses

12x-3-49

We add all the numbers together, and all the variables

12x-52

Back to the equation:

-(12x-52)



We get rid of parentheses

4x-12x+52+12=0

We add all the numbers together, and all the variables

-8x+64=0

We move all terms containing x to the left, all other terms to the right

-8x=-64

x=-64/-8

x=+8

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