4(3+x)=4(4x-1)-68

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Solution for 4(3+x)=4(4x-1)-68 equation: 



4(3+x)=4(4x-1)-68

We move all terms to the left:

4(3+x)-(4(4x-1)-68)=0

We add all the numbers together, and all the variables

4(x+3)-(4(4x-1)-68)=0

We multiply parentheses

4x-(4(4x-1)-68)+12=0



We calculate terms in parentheses: -(4(4x-1)-68), so:

4(4x-1)-68

We multiply parentheses

16x-4-68

We add all the numbers together, and all the variables

16x-72

Back to the equation:

-(16x-72)



We get rid of parentheses

4x-16x+72+12=0

We add all the numbers together, and all the variables

-12x+84=0

We move all terms containing x to the left, all other terms to the right

-12x=-84

x=-84/-12

x=+7

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