4(3+x)=68

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Solution for 4(3+x)=68 equation: 



4(3+x)=68

We move all terms to the left:

4(3+x)-(68)=0

We add all the numbers together, and all the variables

4(x+3)-68=0

We multiply parentheses

4x+12-68=0

We add all the numbers together, and all the variables

4x-56=0

We move all terms containing x to the left, all other terms to the right

4x=56

x=56/4

x=14

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