4(3+y)-y=6+3(y+2)

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Solution for 4(3+y)-y=6+3(y+2) equation: 


Simplifying
4(3 + y) + -1y = 6 + 3(y + 2)
(3 * 4 + y * 4) + -1y = 6 + 3(y + 2)
(12 + 4y) + -1y = 6 + 3(y + 2)

Combine like terms: 4y + -1y = 3y
12 + 3y = 6 + 3(y + 2)

Reorder the terms:
12 + 3y = 6 + 3(2 + y)
12 + 3y = 6 + (2 * 3 + y * 3)
12 + 3y = 6 + (6 + 3y)

Combine like terms: 6 + 6 = 12
12 + 3y = 12 + 3y

Add '-12' to each side of the equation.
12 + -12 + 3y = 12 + -12 + 3y

Combine like terms: 12 + -12 = 0
0 + 3y = 12 + -12 + 3y
3y = 12 + -12 + 3y

Combine like terms: 12 + -12 = 0
3y = 0 + 3y
3y = 3y

Add '-3y' to each side of the equation.
3y + -3y = 3y + -3y

Combine like terms: 3y + -3y = 0
0 = 3y + -3y

Combine like terms: 3y + -3y = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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