4(3-1)+8=19-3(3+4)+6x

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Solution for 4(3-1)+8=19-3(3+4)+6x equation: 



4(3-1)+8=19-3(3+4)+6x

We move all terms to the left:

4(3-1)+8-(19-3(3+4)+6x)=0

We add all the numbers together, and all the variables

-(19-37+6x)+8+42=0

We add all the numbers together, and all the variables

-(19-37+6x)+50=0

We get rid of parentheses

-6x-19+37+50=0

We add all the numbers together, and all the variables

-6x+68=0

We move all terms containing x to the left, all other terms to the right

-6x=-68

x=-68/-6

x=11+1/3

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