4(3-2x)-2(-3x+1)=3(x-2)+5

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Solution for 4(3-2x)-2(-3x+1)=3(x-2)+5 equation: 



4(3-2x)-2(-3x+1)=3(x-2)+5

We move all terms to the left:

4(3-2x)-2(-3x+1)-(3(x-2)+5)=0

We add all the numbers together, and all the variables

4(-2x+3)-2(-3x+1)-(3(x-2)+5)=0

We multiply parentheses

-8x+6x-(3(x-2)+5)+12-2=0



We calculate terms in parentheses: -(3(x-2)+5), so:

3(x-2)+5

We multiply parentheses

3x-6+5

We add all the numbers together, and all the variables

3x-1

Back to the equation:

-(3x-1)



We add all the numbers together, and all the variables

-2x-(3x-1)+10=0

We get rid of parentheses

-2x-3x+1+10=0

We add all the numbers together, and all the variables

-5x+11=0

We move all terms containing x to the left, all other terms to the right

-5x=-11

x=-11/-5

x=2+1/5

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