4(3-2x)-8(x-1)=9(4-2x)

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Solution for 4(3-2x)-8(x-1)=9(4-2x) equation: 



4(3-2x)-8(x-1)=9(4-2x)

We move all terms to the left:

4(3-2x)-8(x-1)-(9(4-2x))=0

We add all the numbers together, and all the variables

4(-2x+3)-8(x-1)-(9(-2x+4))=0

We multiply parentheses

-8x-8x-(9(-2x+4))+12+8=0



We calculate terms in parentheses: -(9(-2x+4)), so:

9(-2x+4)

We multiply parentheses

-18x+36

Back to the equation:

-(-18x+36)



We add all the numbers together, and all the variables

-16x-(-18x+36)+20=0

We get rid of parentheses

-16x+18x-36+20=0

We add all the numbers together, and all the variables

2x-16=0

We move all terms containing x to the left, all other terms to the right

2x=16

x=16/2

x=8

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