4(3-2x)/9-18=-6

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Solution for 4(3-2x)/9-18=-6 equation: 



4(3-2x)/9-18=-6

We move all terms to the left:

4(3-2x)/9-18-(-6)=0

We add all the numbers together, and all the variables

4(-2x+3)/9-18-(-6)=0

We add all the numbers together, and all the variables

4(-2x+3)/9-12=0

We multiply all the terms by the denominator


4(-2x+3)-12*9=0

We add all the numbers together, and all the variables

4(-2x+3)-108=0

We multiply parentheses

-8x+12-108=0

We add all the numbers together, and all the variables

-8x-96=0

We move all terms containing x to the left, all other terms to the right

-8x=96

x=96/-8

x=-12

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