4(3-2x)=-10x+12(x+11)

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Solution for 4(3-2x)=-10x+12(x+11) equation:



4(3-2x)=-10x+12(x+11)
We move all terms to the left:
4(3-2x)-(-10x+12(x+11))=0
We add all the numbers together, and all the variables
4(-2x+3)-(-10x+12(x+11))=0
We multiply parentheses
-8x-(-10x+12(x+11))+12=0
We calculate terms in parentheses: -(-10x+12(x+11)), so:
-10x+12(x+11)
We multiply parentheses
-10x+12x+132
We add all the numbers together, and all the variables
2x+132
Back to the equation:
-(2x+132)
We get rid of parentheses
-8x-2x-132+12=0
We add all the numbers together, and all the variables
-10x-120=0
We move all terms containing x to the left, all other terms to the right
-10x=120
x=120/-10
x=-12

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